More secratary edits
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@ -79,7 +79,7 @@ We have no absolute metric by which to judge each candidate.
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\vspace{2mm}
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Thus, all $I_x$ defined above are independent: \par
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Thus, all $I_x$ defined above are independent:
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the outcome of any $I_a$ does not influence the probabilities of any other $I_b$.
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\vspace{2mm}
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@ -92,4 +92,48 @@ the results of past $I_x$ cannot possibly provide information about future $I_x$
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Given the above realizations, we are left with only one kind of strategy: \par
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We blindly reject the first $k$ applicants, and select the first \say{best-seen} applicant we encounter afterwards.
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All we need to do now is pick the optimal $k$.
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All we need to do now is pick the optimal $k$.
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\pagebreak
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\problem{}
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Consider the secretary problem with a given $n$. \par
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What is the probability distribution of each of $I_1, I_2, ..., I_n$? \par
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\note{That is, what are $\mathcal{P}(I_x = \texttt{0})$ and $\mathcal{P}(I_x = \texttt{1})$ for each $x$?}
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\vfill
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\problem{}
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What is the probability that the $x^\text{th}$ applicant is \textit{not} the best-seen applicant? \par
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In other words, what is the probability we reject the $x^\text{th}$ candidate? \par
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\note{Assuming that $x > k$. Otherwise, the probability of rejection is 1!}
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\vfill
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\problem{}<phisubn>
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Again, consider the secretary problem with a fixed $n$. \par
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If we reject the first $k$ applicants and hire the first \say{best-yet} applicant we encounter, \par
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what is the probability that we select the best candidate? \par
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Call this function $\phi_n(k)$.
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\vfill
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\problem{}
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Find $
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\underset{x \in \{0, ..., n\}}{\text{max}}
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\Bigl(\phi_n(k)\Bigr)
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$ for all $n$ in $\{1, 2, 3, 4, 5\}$.
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\vfill
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\problem{}
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Find $
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\underset{x \in \mathbb{R}}{\text{max}}
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\Bigl(~
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\underset{n \rightarrow \infty}{\text{lim}}
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\phi_n(k)
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~\Bigr)
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$
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\vfill
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