Minor edits

Advanced/Nonstandard Analysis/parts/1 extensions.tex

@@ -51,13 +51,6 @@ An ordered field must satisfy the following properties:
 \definition{}
 An ordered field that contains $\mathbb{R}$ is called a \textit{nonarchimedian extension} of $\mathbb{R}$.
 
-\vfill
-\pagebreak
-
-
-
-
-
 \problem{}
 Show that each of the following is true in any ordered field.
 \begin{enumerate}
@@ -68,15 +61,14 @@ Show that each of the following is true in any ordered field.
 \end{enumerate}
 
 
-\begin{solution}
-	\textbf{Part A:}
-
-	We know that $x^{-1} \times (x^{-1})^{-1} = 1$ \par
-	Thus $x \times (x^{-1} \times (x^{-1})^{-1}) = x \times 1 = x$ \par
-	We can rewrite this as $(x \times x^{-1}) \times (x^{-1})^{-1} = x$ \par
-	When then becomes $1 \times (x^{-1})^{-1} = x$ \par
-	And thus $(x^{-1})^{-1} = x$
-\end{solution}
+%\begin{solution}
+%	\textbf{Part A:}
+%	We know that $x^{-1} \times (x^{-1})^{-1} = 1$ \par
+%	Thus $x \times (x^{-1} \times (x^{-1})^{-1}) = x \times 1 = x$ \par
+%	We can rewrite this as $(x \times x^{-1}) \times (x^{-1})^{-1} = x$ \par
+%	When then becomes $1 \times (x^{-1})^{-1} = x$ \par
+%	And thus $(x^{-1})^{-1} = x$
+%\end{solution}
 
 
 \vfill