From 82064f890c5f4fdc4e3a293e5624a49b248745a9 Mon Sep 17 00:00:00 2001
From: Mark <mark@betalupi.com>
Date: Tue, 30 Jan 2024 22:10:59 -0800
Subject: [PATCH] Minor edits

---
 .../parts/1 extensions.tex                    | 24 +++++++------------
 1 file changed, 8 insertions(+), 16 deletions(-)

diff --git a/Advanced/Nonstandard Analysis/parts/1 extensions.tex b/Advanced/Nonstandard Analysis/parts/1 extensions.tex
index 1df2389..8f8933c 100644
--- a/Advanced/Nonstandard Analysis/parts/1 extensions.tex	
+++ b/Advanced/Nonstandard Analysis/parts/1 extensions.tex	
@@ -51,13 +51,6 @@ An ordered field must satisfy the following properties:
 \definition{}
 An ordered field that contains $\mathbb{R}$ is called a \textit{nonarchimedian extension} of $\mathbb{R}$.
 
-\vfill
-\pagebreak
-
-
-
-
-
 \problem{}
 Show that each of the following is true in any ordered field.
 \begin{enumerate}
@@ -68,15 +61,14 @@ Show that each of the following is true in any ordered field.
 \end{enumerate}
 
 
-\begin{solution}
-	\textbf{Part A:}
-
-	We know that $x^{-1} \times (x^{-1})^{-1} = 1$ \par
-	Thus $x \times (x^{-1} \times (x^{-1})^{-1}) = x \times 1 = x$ \par
-	We can rewrite this as $(x \times x^{-1}) \times (x^{-1})^{-1} = x$ \par
-	When then becomes $1 \times (x^{-1})^{-1} = x$ \par
-	And thus $(x^{-1})^{-1} = x$
-\end{solution}
+%\begin{solution}
+%	\textbf{Part A:}
+%	We know that $x^{-1} \times (x^{-1})^{-1} = 1$ \par
+%	Thus $x \times (x^{-1} \times (x^{-1})^{-1}) = x \times 1 = x$ \par
+%	We can rewrite this as $(x \times x^{-1}) \times (x^{-1})^{-1} = x$ \par
+%	When then becomes $1 \times (x^{-1})^{-1} = x$ \par
+%	And thus $(x^{-1})^{-1} = x$
+%\end{solution}
 
 
 \vfill