Typos
This commit is contained in:
		| @ -224,7 +224,7 @@ A = \lm f .(\tzm{a} ~ \lm a . f(f(a)) ~ \tzm{b}) | ||||
| 	\path[draw = gray] (aa) to (bb); | ||||
| \end{tikzpicture} | ||||
| $$ | ||||
| When we evaluate $A$ with one input, it constructs a new function with the argument we gave it. \par | ||||
| When we evaluate $A$ with one input, it constructs a new function with the argument we give it. \par | ||||
| For example, let's apply $A$ to an arbirary function $N$: | ||||
| $$ | ||||
| 	A~N = | ||||
| @ -242,7 +242,7 @@ $$ | ||||
| 	\end{tikzpicture} | ||||
| $$ | ||||
| Above, $A$ replaced every $f$ in its definition with an $N$. \par | ||||
| You can think of $A$ as a \say{factory} that constructs functions using the inputs we gave it. | ||||
| You can think of $A$ as a \say{factory} that constructs functions using the inputs we provide. | ||||
|  | ||||
| \problem{}<firstcardinal> | ||||
| Let $C = \lm f. (\lm g. \lm x. (g(f(x))))$. What does $B$ do? \par | ||||
|  | ||||
		Reference in New Issue
	
	Block a user