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Mockingbird edits

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Mark
2023-03-28 22:16:39 -07:00
parent 9927c8ff43
commit 48ac646ee4
3 changed files with 15 additions and 17 deletions
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13
Advanced/Mock a Mockingbird/parts/02 kestrel.tex
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@ -16,9 +16,8 @@ Say $A$ is fixated on $B$. Is $A$ fond of $B$?
\begin{solution}
Yes! See the following proof.
\begin{alltt}
\lineno{} let B
\lineno{} let B
\lineno{} let A so that Ax = B
\lineno{} let A
\lineno{} let B so that Ax = B
\lineno{} \thus{} AB = B \qed{}
\end{alltt}
\end{solution}
@ -39,8 +38,8 @@ Show that an egocenteric Kestrel is hopelessly egocentric
\begin{solution}
\begin{alltt}
\lineno{} KK = K
\lineno{} \thus{} (KK)y = K
\lineno{} \thus{} Ky = K \qed{}
\lineno{} \thus{} (KK)y = K \cmnt{By definition of the Kestrel}
\lineno{} \thus{} Ky = K \qed{} \cmnt{By 01}
\end{alltt}
\end{solution}
@ -50,7 +49,7 @@ Show that an egocenteric Kestrel is hopelessly egocentric
\problem{}
Assume the forest contains a Kestrel. \\
Given $L_1$ and $L_2$, show that at least one bird is hopelessly egocentric.
Given the Law of Composition and the Law of the Mockingbird, show that at least one bird is hopelessly egocentric.
\begin{helpbox}[0.75]
\texttt{Def:} $K$ is defined by $(Kx)y = x$ \\
@ -116,7 +115,7 @@ Show that if $K$ is fond of $Kx$, $K$ is fond of $x$.
An egocentric Kestrel must be extremely lonely. Why is this?
\begin{solution}
If a Kestrel is egocenteric, it must be the only bird in the forest:
If a Kestrel is egocenteric, it must be the only bird in the forest!
\begin{alltt}
\lineno{} \cmnt{Given}