Mark/handouts
Mark/handouts
1
0
Fork 0
Code Pull Requests 2 Actions Packages Releases Activity

Typo

Browse Source
This commit is contained in:
Mark 2024-03-25 10:18:23 -07:00
parent 6d5459eaf4
commit 3ca94a0c1a
Signed by: Mark
GPG Key ID: C6D63995FE72FD80
1 changed files with 3 additions and 3 deletions
Show Stats Download Patch File Download Diff File Expand all files Collapse all files

6
Intermediate/Combinatorics/main.tex
View File

@ -198,13 +198,13 @@
\problem{} \problem{}
Now, derive the \textit{multinomial coefficient} $\binom{n}{k_1,k_2,...,k_m}$. \par Now, derive the \textit{multinomial coefficient} $\binom{n}{k_1, k_2, ..., k_m}$. \par
\vspace{1mm} \vspace{1mm}
The multinomial coefficient tells us how many distinct ways there to arrange $n$ objects The multinomial coefficient tells us how many distinct ways there to arrange $n$ objects
of $m$ classes, where each class $i$ contains $k_i$ identical objects. \par of $m$ classes, where each class $i$ contains $k_i$ identical objects. \par
\hint{ \hint{
In \ref{manyballs}, $n = 5$ and $(k_1, k_2, k_3, k_4) = (8, 3, 6, 4)$. \\ In \ref{manyballs}, $n = 21$ and $(k_1, k_2, k_3, k_4) = (8, 3, 6, 4)$. \\
So, the solution to \ref{manyballs} should be given by the multinomial coefficient $\binom{5}{8,3,6,4}$. So, the solution to \ref{manyballs} should be given by the multinomial coefficient $\binom{21}{8,3,6,4}$.
} }