Handout edits
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@ -55,18 +55,12 @@ If you look at our set of constant symbols, you'll see that the only integers we
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\vspace{1mm}
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Say we want the number 2. We could use the function $+$ to define it: $2 \coloneqq [x \text{ where } 1 + 1 = x]$ \par
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We would write this as $2 \coloneqq [x \text{ where } +(1, 1) = x]$ in proper \say{functional} notation.
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To \say{define} an element of a set, we need to write a sentence that is only true for that element. For example, if we want to define 2 in the structure above, we could use the sentence $\varphi(x) = [1 + 1 = x]$. \par
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Clearly, this is only true when $x = 2$.
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\problem{}
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Can we define $-1$ in $\Bigl( \mathbb{Z} ~\big|~ \{0, 1, +, -, <\} \Bigr)$? If so, how?
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\vfill
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\problem{}
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Can we define $-1$ in $\Bigl( \mathbb{Z} ~\big|~ \{0, +, -, <\} \Bigr)$? \par
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\hint{In this problem, $1$ has been removed from the set of constant symbols.}
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Define $-1$ in $\Bigl( \mathbb{Z} ~\big|~ \{0, 1, +, -, <\} \Bigr)$.
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\vfill
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\pagebreak
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@ -87,7 +81,13 @@ A formula can contain one or more \textit{free variables.} These are denoted $\v
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Formulas with free variables let us define \say{properties} that certain objects have. \par
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For example, $x$ is a free variable in the formula $\varphi(x) = [x > 0]$. \par
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$\varphi(3)$ is true and $\varphi(-3)$ is false.
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$\varphi(3)$ is true and $\varphi(-3)$ is false. \par
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\vspace{2mm}
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This \say{free variable} notation is much like the function notation you are used to: \par
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$\varphi(x) = [x > 0]$ is similar to $f(x) = x + 1$, since the values of $\varphi(x)$ and $f(x)$ depend on $x$.
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\definition{Definable Elements}
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Say $S$ is a structure with a universe $U$. \par
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@ -95,7 +95,7 @@ We say an element $e \in U$ is \textit{definable in $S$} if we can write a formu
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\problem{}
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Can we define 2 in the structure $\Bigl( \mathbb{Z^+} ~\big|~ \{4, \times \} \Bigr)$? \par
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Define 2 in the structure $\Bigl( \mathbb{Z^+} ~\big|~ \{4, \times \} \Bigr)$. \par
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\hint{$\mathbb{Z}^+ = \{1, 2, 3, ...\}$. Also, $2 \times 2 = 4$.}
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\begin{solution}
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@ -106,7 +106,8 @@ Can we define 2 in the structure $\Bigl( \mathbb{Z^+} ~\big|~ \{4, \times \} \Bi
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\problem{}
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Try to define 2 in the structure $\Bigl( \mathbb{Z} ~\big|~ \{4, \times \} \Bigr)$.
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Try to define 2 in the structure $\Bigl( \mathbb{Z} ~\big|~ \{4, \times \} \Bigr)$. \par
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Why can't you do it?
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\begin{solution}
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This isn't possible. We could try $\varphi(x) = [x \times x = 4]$, but this is satisfied by both $2$ and $-2$. \par
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