2023-10-05 11:23:03 -07:00

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\section{Recursion}
Say we want a function that computes the factorial of a positive integer. Here's one way we could define it:
$$
x! = \begin{cases}
x \times (x-1)! & x \neq 0 \\
1 & x = 0
\end{cases}
$$
We cannot re-create this in lambda calculus, since we aren't given a way to recursively call functions.
\vspace{2mm}
One could think that $A = \lm a. A~a$ is a recursive function. In fact, it is not. \par
Remember that such \say{definitions} aren't formal structures in lambda calculus. \par
They're just shorthand that simplifies notation.
\begin{instructornote}
We're talking about recursion, and \textit{computability} isn't far away. At one point or another, it may be good to give the class a precise definition of \say{computable by lambda calculus:}
\vspace{4ex}
Say we have a device that reduces a $\lm$ expression to $\beta$-normal form. We give it an expression, and the machine simplifies it as much as it can and spits out the result.
\vspace{1ex}
An algorithm is \say{computable by lambda calculus} if we can encode its input in an expression that resolves to the algorithm's output.
\end{instructornote}
\problem{}
Write an expression that resolves to itself. \par
\note{Your answer should be quite short.}
\vspace{1ex}
This expression is often called $\Omega$, after the last letter of the Greek alphabet. \par
$\Omega$ useless on its own, but it gives us a starting point for recursion.
\begin{solution}
$\Omega = M~M = (\lm x . xx) (\lm x . xx)$
\vspace{1ex}
An uninspired mathematician might call the Mockingbird $\omega$, \say{little omega}.
\end{solution}
\vfill
\definition{}
This is the \textit{Y-combinator}, easily the most famous $\lm$ expression. \par
You may notice that it's just $\Omega$, put to work.
$$
Y = \lm f . (\lm x . f(x~x))(\lm x . f(x~x))
$$
\problem{}
What does this thing do? \par
Evaluate $Y f$.
\vfill
\pagebreak