<html><head><meta name="color-scheme" content="light dark"></head><body><pre style="word-wrap: break-word; white-space: pre-wrap;">% use [nosolutions] flag to hide solutions.
% use [solutions] flag to show solutions.
\documentclass[
	solutions,
	singlenumbering
]{../../resources/ormc_handout}
\usepackage{../../resources/macros}



\uptitlel{Advanced 1}
\uptitler{Summer 2023}
\title{The Size of Sets}
\subtitle{Prepared by \githref{Mark} on \today{}}

\begin{document}

	\maketitle

	\input{parts/0 sets.tex}
	\input{parts/1 really big.tex}
	\input{parts/2 cartesian.tex}
	\input{parts/3 functions.tex}
	\input{parts/4 enumeration.tex}
	%\input{parts/5 dense.tex}
	\input{parts/6 uncountable.tex}


	%\vfill
	%\pagebreak

	%\section{Bonus Problems}

	%\problem{}
	%Using only sets, how can we build an ordered pair $(a, b)$? \par
	%$(a, b)$ should be equal to $(c, d)$ if and only if $a = b$ and $c = d$. \par
	%Of course, $(a, b) \neq (b, a)$.

	%\begin{solution}
	%	$(a, b) = \{ \{a\}, \{a, b\}\}$
	%\end{solution}

	%\problem{}
	%Suppose $f: A \to B$ and $g: B \to C$ are both one-to-one. Must $h(x) = g(f(x))$ be one-to-one? \par
	%Provide a proof or a counterexample.

	%\vfill

	%\problem{}
	%Suppose $f: A \to B$ and $g: B \to C$ are both onto. Must $h(x) = g(f(x))$ be onto? \par
	%Provide a proof or a counterexample.

	%\vfill
	%\pagebreak

\end{document}</pre></body></html>