\section{Dice} \definition{} A \textit{die} is a device that randomly selects a positive integer from a finite list of options. For example, the standard 6-sided die selects a value from $[1,2,3,4,5,6]$. We may have many sides with the same value, as in $[1, 1, 2, 3]$. To describe a die with a generating function, let $a_k$ be the number of times $k$ appears as a side of the die and consider $a_0 + a_1x + x_2x^2 + ... $. \par A die has a finite number of sides, so this will be a regular polynomial. \problem{} What is the generating function of the standard 6-sided die? \begin{solution} $x + x^2 + x^3 + x^4 + x^5 + x^6$ \end{solution} \vfill \problem{} What is the generating function of the die with sides $[1, 2, 3, 5]$? \begin{solution} $2x + x^2 + x^3 + x^5$ \end{solution} \vfill \problem{} Let $A(x)$ and $B(x)$ be the generating functions of two dice. \par What is the significance of $A(1)$? \begin{solution} $A(1) = $ the number of sides on the die \end{solution} \vfill \problem{} Using formulas we found earlier, show that the $k^\text{th}$ coefficient of $A(x)B(x)$ is the number of ways to roll $k$ as the sum of the two dice. \begin{solution} The $k^\text{th}$ coefficient of $A(x)B(x)$ is... \begin{align*} a_0b_k + a_1b_{k+1} + ... + a_kb_0 \\ &=~ \text{count}(A = 0; B = k) + ... + \text{count}(A = k; B = 0) \\ &=~ \text{number of ways} A + B = k \end{align*} \end{solution} \vfill \pagebreak \problem{} Find a generating function for the sequence $c_0, c_1, ...$, where $c_k$ is the probability that the sum of the two dice is $k$. \begin{solution} \begin{equation*} c_k = \frac{\text{number of ways sum } = k}{\text{number of total outcomes}} = \frac{\text{number of ways sum } = k}{A(1)B(1)} \end{equation*} So, \begin{equation*} c_0 + c_1x + c_2x^2 = \frac{A(x)B(x)}{A(1)B(1)} \end{equation*} \end{solution} \vfill \problem{} Using generating functions, find two six-sided dice whose sum has the same distribution as the sum of two standard six-sided dice? \par That is, for any integer $k$, the number if ways that the sum of the two nonstandard dice rolls as $k$ is equal to the numer of ways the sum of two standard dice rolls as $k$. \hint{factor polynomials.} \begin{solution} We need a different factorization of \begin{equation*} (x + x^2 + x^3 + x^4 + x^5 + x^6)^2 = A(x)B(x) \end{equation*} We can use \begin{equation*} (x + 2x^2 + 2x^3 + x^4) (x + x^3 + x^4 + x^5 + x^6 + x^8) \end{equation*} \end{solution} \vfill \pagebreak