\section{A Review of Functions} \definition{} A \textit{function} or \textit{map} $f$ from a set $A$ (the \textit{domain}, $\mathcal{D}$) to a set $B$ (the \textit{range}, $\mathcal{R}$) is a rule that assigns an element of $B$ to each element of $A$. We write this as $f: A \to B$. \vspace{2mm} Consider a function $f: \mathbb{Z} \to \mathbb{Z}$. If $f(1) = 2$, we say that 2 is the \textit{image} of 1 and 1 is a \textit{preimage} of 2 under $f$. \vspace{2mm} An element in a function's domain must have exactly one image. However, an element in the range may have more than one preimage. \problem{} Consider the function $f: \mathbb{R} \to \mathbb{R}^+ \cap \{0\}$ defined by $f(x) = x^2$ \begin{itemize} \item[-] What is the image of 2? \item[-] What are the preimages of 9? \end{itemize} \vfill \definition{} We say a map is \textit{one-to-one} if $a = b \implies f(a) = f(b)$ for all $a, b$ in the domain. In other words, this means that each element of the range has at most one preimage. \definition{} We say a map $f$ is \textit{onto} if, for every $y \in \mathcal{R}$, there exists an $x \in \mathcal{D}$ so that $f(x) = y$. In other words, this means that every $y$ in the range has a preimage in the domain. \problem{} Find a function that is... \begin{enumerate} \item[-] neither one-to-one nor onto \item[-] one-to-one and not onto \item[-] not one-to-one, but onto \item[-] both one-to-one and onto \end{enumerate} We say a function that is both one-to-one and onto is \textit{bijective}. \vfill \pagebreak \definition{} Let $f: A \to B$ and $g: B \to C$. We can define a new function $(g \circ f): A \to C$, where $(g \circ f)(a) = g(f(a))$. This is called \textit{composition}. \problem{} Suppose $f: A \to B$ and $g: B \to C$ are both one-to-one. Must $(g \circ f)$ be one-to-one? Provide a proof or a counterexample. \vfill \problem{} Suppose $f: A \to B$ and $g: B \to C$ are both onto. Must $(g \circ f)$ be onto? Provide a proof or a counterexample. \vfill \pagebreak \section{A Review of Modular Arithmetic} \definition{} $\mathbb{Z}_n$ is the set of integers mod $n$. For example, $\mathbb{Z}_5 = \{0, 1, 2, 3, 4\}$. \\ You should all be familiar with modular arithmetic. \definition{} The inverse of an element $a$ in $\mathbb{Z}_n$ is a $b$ so that $a \times b \equiv 1$. \\ Not all elements of $\mathbb{Z}_n$ have an inverse. Those that do are called \textit{units}. \\ \vspace{2mm} The set of all units in $\mathbb{Z}_n$ is written $\mathbb{Z}_n^\times$ \\ Read this as \say{$\mathbb{Z}$ mod $n$ cross} \problem{} What are the elements of $\mathbb{Z}_5^\times$? \begin{solution} $\{1, 2, 3, 4\}$ \end{solution} \vfill \problem{} Create an addition table for $\mathbb{Z}_4$ and a multiplication table for $(\mathbb{Z}_5)^\times$ \begin{center} \begin{tabular}{c | c c c c} + & 0 & 1 & 2 & 3 \\ \hline 0 & ? & ? & ? & ? \\ 1 & ? & ? & ? & ? \\ 2 & ? & ? & ? & ? \\ 3 & ? & ? & ? & ? \\ \end{tabular} \end{center} \begin{solution} \begin{center} \begin{tabular}{c | c c c c} + & 0 & 1 & 2 & 3 \\ \hline 0 & 0 & 1 & 2 & 3 \\ 1 & 1 & 2 & 3 & 0 \\ 2 & 2 & 3 & 0 & 1 \\ 3 & 3 & 0 & 1 & 2 \\ \end{tabular} \hspace{1cm} \begin{tabular}{c | c c c c} \times & 1 & 2 & 3 & 4 \\ \hline 1 & 1 & 2 & 3 & 4 \\ 2 & 2 & 4 & 1 & 3 \\ 3 & 3 & 1 & 4 & 2 \\ 4 & 4 & 3 & 2 & 1 \\ \end{tabular} \end{center} \end{solution} \vfill \vfill \pagebreak