\section{Division}

Now that you can multiply, division should be easy. All you need to do is work backwards. \\
Let's look at our first example again: $3 \times 2 = 6$.

\medskip

We can easily see that $6 \div 3 = 2$

\begin{center}
\begin{tikzpicture}[scale=1]
	\cdscale{\cdscalefn(2)}{1}{C}
	\cdscale{0}{0}{D}

	\slideruleind
		{\cdscalefn(6)}
		{1}
		{Align here}

	\slideruleind
		{\cdscalefn(2)}
		{1}
		{2}
\end{tikzpicture}
\end{center}

and that $6 \div 2 = 3$:
\begin{center}
\begin{tikzpicture}[scale=1]
	\cdscale{\cdscalefn(3)}{-3}{C}
	\cdscale{0}{-4}{D}


	\slideruleind
		{\cdscalefn(6)}
		{-3}
		{Align here}

	\slideruleind
		{\cdscalefn(3)}
		{-3}
		{3}

\end{tikzpicture}
\end{center}

If your left-hand index is off the scale, read the right-hand one. \\
Consider $42.25 \div 6.5 = 6.5$:

\begin{center}
\begin{tikzpicture}[scale=1]
	\cdscale{\cdscalefn(6.5) - \cdscalefn(10)}{1}{C}
	\cdscale{0}{0}{D}


	\slideruleind
		{\cdscalefn(4.225)}
		{1}
		{Align here}

	\slideruleind
		{\cdscalefn(6.5)}
		{1}
		{6.5}

\end{tikzpicture}
\end{center}

Place your decimal points carefully.

\vfill

\problem{}
Compute the following using your slide rule. \par

\begin{enumerate}
	\item $135 \div 15$
	\item $68.2 \div 0.575$
	\item $(118 \times 0.51) \div 6.6$
\end{enumerate}

\begin{solution}
	\begin{enumerate}
		\item $135 \div 15 = 9$
		\item $68.2 \div 0.575 = 118.609$
		\item $(118 \times 0.51) \div 6.6 = 9.118$
	\end{enumerate}
\end{solution}

\vfill
\pagebreak