Minor edits

Advanced/Continued Fractions/parts/02 part B.tex

@@ -115,7 +115,7 @@ Similarly derive the formula $p_nq_{n-2}-p_{n-2}q_n = (-1)^{n-2}a_n$.
 \problem{}<diff>
 Recall $C_n=p_n/q_n$.
 Show that $C_n-C_{n-1}=\frac{(-1)^{n-1}}{q_{n-1}q_n}$
-and $C_n-C_{n-2}=\frac{(-1)^{n-2}a_n}{q_{n-2}q_n}$.
+and $C_n-C_{n-2}=\frac{(-1)^{n-2}a_n}{q_{n-2}q_n}$. \par
 \hint{Use \ref{form1} and $p_nq_{n-2}-p_{n-2}q_n = (-1)^{n-2}a_n$ respectively}
 
 In \ref{sqrt5}, the value $\alpha-C_n$ alternated between negative and positive