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@ -60,8 +60,8 @@ the probability that the sum of the two dice is $k$.
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\begin{equation*}
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c_k
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= \frac{\text{number of ways sum } = k}{\text{number of total outcomes}}
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= \frac{\text{number of ways sum } = k}{A(1)B(1)}
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= \frac{\text{number of ways sum} = k}{\text{number of total outcomes}}
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= \frac{\text{number of ways sum} = k}{A(1)B(1)}
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\end{equation*}
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So,
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