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Mark 2025-01-09 11:39:11 -08:00
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@ -60,8 +60,8 @@ the probability that the sum of the two dice is $k$.
\begin{equation*} \begin{equation*}
c_k c_k
= \frac{\text{number of ways sum } = k}{\text{number of total outcomes}} = \frac{\text{number of ways sum} = k}{\text{number of total outcomes}}
= \frac{\text{number of ways sum } = k}{A(1)B(1)} = \frac{\text{number of ways sum} = k}{A(1)B(1)}
\end{equation*} \end{equation*}
So, So,