Typos
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@ -1,7 +1,7 @@
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% use [nosolutions] flag to hide solutions.
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% use [nosolutions] flag to hide solutions.
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% use [solutions] flag to show solutions.
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% use [solutions] flag to show solutions.
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\documentclass[
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\documentclass[
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solutions,
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nosolutions,
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singlenumbering
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singlenumbering
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]{../../resources/ormc_handout}
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]{../../resources/ormc_handout}
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@ -10,9 +10,9 @@ Draw $\mathbb{Z}^2$.
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\definition{}
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\definition{}
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We say a set of vectors $\{v_1, v_2, ..., v_n\}$ \textit{generates} $\mathbb{Z}^n$ if every lattice point can be written uniquely as
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We say a set of vectors $\{v_1, v_2, ..., v_n\}$ \textit{generates} $\mathbb{Z}^n$ if every lattice point can be written uniquely as
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$$
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$$
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a_1v_1 + a_2v_2 + ... a_nv_n
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a_1v_1 + a_2v_2 + ... + a_nv_n
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$$
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$$
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for integer coeficcients $a_i$.
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for integer coefficients $a_i$.
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\problem{}
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\problem{}
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Which of the following generate $\mathbb{Z}^3$?
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Which of the following generate $\mathbb{Z}^3$?
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@ -37,13 +37,13 @@ Find a set of vectors that generates $\mathbb{Z}^n$.
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\vfill
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\vfill
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\pagebreak
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\pagebreak
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\problem{}
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\definition{}
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A \textit{fundamental region} of a lattice is the parallelepiped spanned by a generating set. The exact shape of this region depends on the generating set we use.
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A \textit{fundamental region} of a lattice is the parallelepiped spanned by a generating set. The exact shape of this region depends on the generating set we use.
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\vfill
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\vfill
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\problem{}
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\problem{}
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Draw two fundamental reions of $\mathbb{Z}^2$ using two different generating sets. Verify that their volumes are the same.
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Draw two fundamental regions of $\mathbb{Z}^2$ using two different generating sets. Verify that their volumes are the same.
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\vfill
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\vfill
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\pagebreak
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\pagebreak
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@ -31,7 +31,7 @@ The following picture gives the idea for the proof of Blichfeldt's theorem. Expl
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\problem{}
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\problem{}
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Let $X$ be a region $X$ of volume $k$. How many integral points must $X$ contain after a translation?
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Let $X$ be a region $\in \mathbb{R}^2$ of volume $k$. How many integral points must $X$ contain after a translation?
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\vfill
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\vfill
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