Update cetz & ci
This commit is contained in:
@ -1,21 +1,18 @@
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#import "@local/handout:0.1.0": *
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#import "../macros.typ": *
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#import "@preview/cetz:0.3.1"
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#import "@preview/cetz:0.4.2"
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= Tropical Polynomials
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#definition()
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A _polynomial_ is an expression formed by adding and multiplying numbers and a variable $x$. \
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Every polynomial can be written as
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#align(
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center,
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box(
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inset: 3mm,
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$
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c_0 + c_1 x + c_2 x^2 + ... + c_n x^n
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$,
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),
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)
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#align(center, box(
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inset: 3mm,
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$
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c_0 + c_1 x + c_2 x^2 + ... + c_n x^n
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$,
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))
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for some nonnegative integer $n$ and coefficients $c_0, c_1, ..., c_n$. \
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The _degree_ of a polynomial is the largest $n$ for which $c_n$ is nonzero.
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@ -43,15 +40,12 @@ In this section, we will analyze tropical polynomials:
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#definition()
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A _tropical_ polynomial is a polynomial that uses tropical addition and multiplication. \
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In other words, it is an expression of the form
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#align(
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center,
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box(
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inset: 3mm,
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$
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c_0 #tp (c_1 #tm x) #tp (c_2 #tm x^2) #tp ... #tp (c_n #tm x^n)
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$,
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),
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)
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#align(center, box(
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inset: 3mm,
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$
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c_0 #tp (c_1 #tm x) #tp (c_2 #tm x^2) #tp ... #tp (c_n #tm x^n)
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$,
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))
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where all exponents represent repeated tropical multiplication.
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#pagebreak() // MARK: page
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@ -66,7 +60,7 @@ Draw a graph of the tropical polynomial $f(x) = x^2 #tp 1x #tp 4$. \
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#if_no_solutions(graphgrid(none))
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#solution([
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$f(x) = min(2x , 1+x, 4)$, which looks like:
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$f(x) = min(2x, 1+x, 4)$, which looks like:
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#graphgrid({
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import cetz.draw: *
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@ -90,15 +84,12 @@ Draw a graph of the tropical polynomial $f(x) = x^2 #tp 1x #tp 4$. \
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#problem()
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Now, factor $f(x) = x^2 #tp 1x #tp 4$ into two polynomials with degree 1. \
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In other words, find $r$ and $s$ so that
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#align(
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center,
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box(
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inset: 3mm,
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$
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x^2 #tp 1x #tp 4 = (x #tp r)(x #tp s)
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$,
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),
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)
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#align(center, box(
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inset: 3mm,
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$
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x^2 #tp 1x #tp 4 = (x #tp r)(x #tp s)
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$,
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))
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we will call $r$ and $s$ the _roots_ of $f$.
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@ -159,15 +150,19 @@ Find a factorization of $f$ in the form $a(x #tp r)(x#tp s)$.
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#solution([
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We (tropically) factor out $-2$ to get
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#eqnbox($
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f(x) = -2(x^2 #tp 2x #tp 10)
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$)
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#eqnbox(
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$
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f(x) = -2(x^2 #tp 2x #tp 10)
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$,
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)
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by the same process as the previous problem, we get
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#eqnbox($
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f(x) = -2(x #tp 2)(x #tp 8)
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$)
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#eqnbox(
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$
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f(x) = -2(x #tp 2)(x #tp 8)
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$,
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)
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])
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#v(1fr)
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@ -236,11 +231,11 @@ Graph $f(x) = 1x^2 #tp 3x #tp 5$.
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#problem()
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Find a factorization of $f$ in the form $a(x #tp r)(x#tp s)$.
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#solution(
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eqnbox($
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#solution(eqnbox(
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$
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f(x) = 1x^2 #tp 3 x #tp 5 = 1(x #tp 2)^2
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$),
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)
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$,
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))
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#v(1fr)
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@ -263,23 +258,21 @@ Graph $f(x) = 2x^2 #tp 4x #tp 4$.
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#if_no_solutions(graphgrid(none))
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#solution(
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graphgrid({
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import cetz.draw: *
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let step = 0.75
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#solution(graphgrid({
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import cetz.draw: *
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let step = 0.75
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dotline((0, 2 * step), (3 * step, 8 * step))
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dotline((0, 4 * step), (5 * step, 8 * step))
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dotline((0, 4 * step), (8 * step, 4 * step))
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dotline((0, 2 * step), (3 * step, 8 * step))
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dotline((0, 4 * step), (5 * step, 8 * step))
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dotline((0, 4 * step), (8 * step, 4 * step))
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line(
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(0, 2 * step),
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(1 * step, 4 * step),
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(7.5 * step, 4 * step),
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stroke: 1mm + oblue,
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)
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}),
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)
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line(
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(0, 2 * step),
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(1 * step, 4 * step),
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(7.5 * step, 4 * step),
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stroke: 1mm + oblue,
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)
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}))
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#problem()
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@ -325,7 +318,7 @@ Find a formula for $B$ in terms of $a$, $b$, and $c$. \
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#solution([
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If we want to factor $a(x^2 #tp (b-a)x #tp (c-a))$, we need to find $r$ and $s$ so that
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- $min(r,s) = b-a$, and
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- $min(r, s) = b-a$, and
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- $r + s = c - a$
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#v(2mm)
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@ -341,9 +334,8 @@ Find a formula for $B$ in terms of $a$, $b$, and $c$. \
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*Case 2:* If $b > (a + c #sym.div) 2$, then
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$
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accent(f, macron)(x)
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&= a x^2 #tp ((a+c)/2)x #tp c \
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&= a(x #tp (c-a)/2)^2
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accent(f, macron)(x) & = a x^2 #tp ((a+c)/2)x #tp c \
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& = a(x #tp (c-a)/2)^2
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$
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has the same graph as $f$, and thus $B = (a+c) #sym.div 2$
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