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@ -88,7 +88,7 @@ Given some $y$, what is the probability that all five $\mathcal{X}_i$ are smalle
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Say we have a random variable $\mathcal{X}$ which we observe $n$ times. \note{(for example, we repeatedly roll a die)}
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Say we have a random variable $\mathcal{X}$ which we observe $n$ times. \note{(for example, we repeatedly roll a die)}
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We'll arrange these observations in increasing order, labeled $x_1 < x_2 < ... < x_n$. \par
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We'll arrange these observations in increasing order, labeled $x_1 < x_2 < ... < x_n$. \par
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Under this definition, $x_i$ is called the \textit{$i^\text{th}$ order statistic}---the $i^\text{th}$ smallest sample of $\mathcal{X}$.
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Under this definition, $x_i$ is called the \textit{$i^\text{th}$ order statistic}---the $i^\text{th}$ smallest sample of $\mathcal{X}$.
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a
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\problem{}<ostatone>
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\problem{}<ostatone>
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Say we have a random variable $\mathcal{X}$ uniformly distributed on $[0, 1]$, of which we take $5$ observations. \par
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Say we have a random variable $\mathcal{X}$ uniformly distributed on $[0, 1]$, of which we take $5$ observations. \par
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@ -188,10 +188,6 @@ reject the first $e^{-1} \times n$ candidates, and select the next \say{best-yet
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How effective is this strategy for the ranked secretary problem? \par
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How effective is this strategy for the ranked secretary problem? \par
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Find the expected rank of the applicant we select using this strategy.
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Find the expected rank of the applicant we select using this strategy.
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\begin{solution}
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Coming soon.
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\end{solution}
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\vfill
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\vfill
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@ -200,7 +196,8 @@ Assuming we use the same kind of strategy as before (reject $k$, select the next
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show that $k = \sqrt{n}$ optimizes the expected rank of the candidate we select.
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show that $k = \sqrt{n}$ optimizes the expected rank of the candidate we select.
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\begin{solution}
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\begin{solution}
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This is a difficult bonus problem. Solution coming later.
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This is a difficult bonus problem. see
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\texttt{Neil Bearden, J. (2006). A new secretary problem with rank-based selection and cardinal payoffs.}
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\end{solution}
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\end{solution}
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\vfill
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\vfill
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