Symmetric group edits

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2024-11-12 20:08:33 -08:00
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\section{Cycle Notation}
\definition{Order}
The \textit{order} of a permutation $f$ is the smallest positive $n$ so that $f^n(x) = x$ for all $x$. \par
In other words: if we repeat this permutation $n$ times, we get back to where we started. \par
Note that the order is given by the \textit{smallest} positive integer $n$. There may be more than one!
The \textit{order} of a permutation $f$ is the \textbf{smallest} positive $n$ so that $f^n(x) = x$ for all $x$. \par
If we repeatedly apply a permutation with order $n$, we will get back to where we started after $n$ steps. \par
\vspace{2mm}
@ -38,9 +36,8 @@ For example, consider $[2134]$. This permutation has order $2$, as we clearly se
\line{4b}{4c}
\end{tikzpicture}
\end{center}
Of course, swapping the first two elements of a list twice changes nothing. \par
Thus, $[2134]$ is its own inverse, and has an order of two. \par
Naturally, the identity permutation has order one.
Swapping the first two elements of a list twice changes nothing. \par
Thus, $[2134]$ has an order of two.
\problem{}
@ -51,7 +48,7 @@ How about $[4321]$? \par
\vfill
\problem{Bonus}
\problem{}
Show that all permutations (on a finite set) have a well-defined order. \par
In other words, show that there is always an integer $n$ so that $f^n(x) = x$.
@ -59,12 +56,17 @@ In other words, show that there is always an integer $n$ so that $f^n(x) = x$.
\definition{Composition}<compdef>
The \textit{composition} of two permutations $f$ and $g$ is the permutation $h(x) = f(g(x))$. \par
The usual notation for this is $f \circ g$, but we'll simply write $fg$.
We'll denote this as $fg$---that is, by simply writing the permutations we're composing next to each other.
\problem{}
Show that function composition is associative. \par
That is, show that $f(gh) = (fg)h$.
\vfill
\problem{}
What is $[1324][4321]$? \par
How about $[321][213][231]$? \par
\hint{is composition is left or right-associative? See \ref{compdef}}
\vfill