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\section{Structures}
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\definition{}<def:language>
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A \textit{language} is a set of meaningless objects. Here are a few examples:
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\definition{}
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A \textit{universe} is a set of meaningless objects. Here are a few examples:
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\begin{itemize}
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\item $\{a, b, ..., z\}$
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\item $\{0, 1\}$
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\item $\mathbb{Z}$, $\mathbb{R}$, etc.
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\end{itemize}
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Every language comes with the equality check $=$, which checks if two elements are the same.
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\definition{}
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A \textit{structure} over a language $\mathcal{L}$ consists of a set of symbols. \par
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The purpose of a structure is to give a language meaning.
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A \textit{structure} consists of a universe $U$ and set of symbols. \par
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A structure's symbols give meaning to the objects in its universe.
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\vspace{2mm}
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Symbols generally come in three types:
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\begin{itemize}
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\item Constant symbols, which let us specify specific elements of our language. \par
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\item Constant symbols, which let us specify specific elements of our universe. \par
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Examples: $0, 1, \frac{1}{2}, \pi$
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\vspace{2mm}
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\item Function symbols, which let us navigate between elements of our language. \par
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\item Function symbols, which let us navigate between elements of our universe. \par
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Examples: $+, \times, \sin{x}, \sqrt{x}$
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\vspace{2mm}
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\item Relation symbols, which let us compare elements of our language. \par
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\item Relation symbols, which let us compare elements of our universe. \par
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Examples: $<, >, \leq, \geq$ \par
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The symbol $=$ is \textbf{not} a relation. Why? \hint{See \ref{def:language}}
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\vspace{2mm}
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\end{itemize}
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The equality check $=$ is \textbf{not} a relation symbol. It is included in every structure by default.
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\vspace{3mm}
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@ -47,7 +44,7 @@ $$
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\vspace{2mm}
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This is a structure over $\mathbb{Z}$ with the following symbols:
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This is a structure with the universe $\mathbb{Z}$ that contains the following symbols:
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\begin{itemize}
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\item Constants: \tab $\{0, 1\}$
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\item Functions: \tab $\{+, -\}$
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@ -86,10 +83,17 @@ A \textit{formula} in a structure $S$ is a well-formed string of constants, func
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You already know what a \say{well-formed} string is: $1 + 1$ is fine, $\sqrt{+}$ is nonsense. \par
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For the sake of time, I will not provide a formal definition. It isn't particularly interesting.
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\vspace{2mm}
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A formula can contain one or more \textit{free variables.} These are denoted $\varphi{(a, b, ...)}$. \par
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Formulas with free variables let us define \say{properties} that certain objects have. \par
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For example, $x$ is a free variable in the formula $\varphi(x) = x > 0$. \par
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$\varphi(3)$ is true and $\varphi(-3)$ is false.
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\definition{Definable Elements}
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Say $S$ is a structure over a language $\mathcal{L}$. \par
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We say an element $e$ of $\mathcal{L}$ is \textit{definable in $S$} if we can write a formula that only $e$ satisfies.
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Say $S$ is a with a universe $U$. \par
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We say an element $e \in U$ is \textit{definable in $S$} if we can write a formula that only $e$ satisfies.
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\problem{}
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@ -104,10 +108,10 @@ Can we define 2 in the structure $\Bigl( \mathbb{Z^+} ~\big|~ \{4, \times \} \Bi
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\problem{}
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Can we define 2 in the structure $\Bigl( \mathbb{Z} ~\big|~ \{4, \times \} \Bigr)$?
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Try to define 2 in the structure $\Bigl( \mathbb{Z} ~\big|~ \{4, \times \} \Bigr)$.
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\begin{solution}
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No. We could try $[x \text{ where } x \times x = 4]$, but this is satisfied by both $2$ and $-2$. \\
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This isn't possible. We could try $[x \text{ where } x \times x = 4]$, but this is satisfied by both $2$ and $-2$. \\
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We have no way to distinguish between negative and positive numbers.
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\end{solution}
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