@ -32,7 +32,7 @@
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\def\bra#1{\left\langle#1\right|}
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% TODO: spend more time on probabalistic bits.
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% TODO: spend more time on probabalastic bits.
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% This could even be its own handout, especially
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% for younger classes!
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@ -498,7 +498,7 @@ Compute the following product:
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\generic{Remark:}
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Also, recall that every matrix is linear map, and that every linear map may be written as a matrix. \par
 | 
			
		||||
We often use the terms \textit{matrix}, \textit{transformation}, and \textit{linear map} interchangably.
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We often use the terms \textit{matrix}, \textit{transformation}, and \textit{linear map} interchangeably.
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\pagebreak
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@ -18,7 +18,7 @@ $\ket{0}$ is pronounced \say{ket zero,} and $\ket{1}$ is pronounced \say{ket one
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\note[Note]{$\bra{0}$ is called a \say{bra,} but we won't worry about that for now.}
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\vspace{2mm}
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This is very similiar to the \say{box} $[~]$ notation we used for probabilistic bits. \par
 | 
			
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This is very similar to the \say{box} $[~]$ notation we used for probabilistic bits. \par
 | 
			
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As before, we will write $\ket{0} = \left[\begin{smallmatrix} 1 \\ 0 \end{smallmatrix}\right]$
 | 
			
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and $\ket{1} = \left[\begin{smallmatrix} 0 \\ 1 \end{smallmatrix}\right]$.
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@ -64,7 +64,7 @@ and like $X$ otherwise. The two circuits above illustrate this fact---take a loo
 | 
			
		||||
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\vspace{2mm}
 | 
			
		||||
Of course, we can give a gate multiple controls. \par
 | 
			
		||||
An $X$ gate with multiplie controls behaves like an $X$ gate if...
 | 
			
		||||
An $X$ gate with multiple controls behaves like an $X$ gate if...
 | 
			
		||||
\begin{itemize}
 | 
			
		||||
	\item all non-inverted controls are $\ket{1}$, and
 | 
			
		||||
	\item all inverted controls are $\ket{0}$
 | 
			
		||||
 | 
			
		||||
@ -1,7 +1,8 @@
 | 
			
		||||
\section{Quantum Teleportation}
 | 
			
		||||
 | 
			
		||||
Superdense coding lets us convert quantum bandwidth into classical bandwidth. \par
 | 
			
		||||
Quantum teleporation does the opposite, using two classical bits and an entangled pair to transmit a quantum state.
 | 
			
		||||
Quantum teleportation does the opposite, using two classical bits and an entangled pair
 | 
			
		||||
to transmit a quantum state.
 | 
			
		||||
 | 
			
		||||
\generic{Setup:}
 | 
			
		||||
Again, suppose Alice and Bob each have half of a $\ket{\Phi^+}$ state. \par
 | 
			
		||||
@ -131,7 +132,7 @@ With an informal proof, show that it is not possible to use superdense coding to
 | 
			
		||||
more than two classical bits through an entangled two-qubit quantum state.
 | 
			
		||||
 | 
			
		||||
\begin{solution}
 | 
			
		||||
	If superdense coding was any more efficient, we could repeatedly apply superdense coding and quantum teleporation,
 | 
			
		||||
	If superdense coding was any more efficient, we could repeatedly apply superdense coding and quantum teleportation,
 | 
			
		||||
	to compress an arbitrary number of bits into two \say{seed} bits.
 | 
			
		||||
 | 
			
		||||
	\linehack{}
 | 
			
		||||
 | 
			
		||||
		Reference in New Issue
	
	Block a user