Merge branch 'master' of ssh://git.betalupi.com:33/Mark/ormc-handouts
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commit
5362154b4b
@ -55,7 +55,7 @@ What is the size of $\mathbb{B}^n$?
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% NOTE: this is time-travelled later in the handout.
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% if you edit this, edit that too.
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\generic{Remark:}
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\cgeneric{Remark}
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Consider a single classical bit. It takes states in $\{\texttt{0}, \texttt{1}\}$, picking one at a time. \par
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The states \texttt{0} and \texttt{1} are fully independent. They are completely disjoint; they share no parts. \par
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We'll therefore say that \texttt{0} and \texttt{1} \textit{orthogonal} (or equivalently, \textit{perpendicular}). \par
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@ -16,7 +16,7 @@ What is the set of possible states of two bits (i.e, $\mathbb{B}^2$)?
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\generic{Remark:}
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\cgeneric{Remark}
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When we have two bits, we have four orthogonal states:
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$\overrightarrow{00}$, $\overrightarrow{01}$, $\overrightarrow{10}$, and $\overrightarrow{11}$. \par
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We need four dimensions to draw all of these vectors, so I can't provide a picture... \par
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@ -42,7 +42,7 @@ with respect to the orthonormal basis $\{\overrightarrow{00}, \overrightarrow{01
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\generic{Remark:}
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\cgeneric{Remark}
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So, we represent each possible state as an axis in an $n$-dimensional space. \par
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A set of $n$ bits gives us $2^n$ possible states, which forms a basis in $2^n$ dimensions.
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@ -38,7 +38,7 @@ A \textit{normalized vector} (also called a \textit{unit vector}) is a vector wi
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\end{tcolorbox}
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\generic{Remark:}
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\cgeneric{Remark}
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Just like a classical bit, a \textit{quantum bit} (or \textit{qubit}) can take the values $\ket{0}$ and $\ket{1}$. \par
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However, \texttt{0} and \texttt{1} aren't the only states a qubit may have.
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@ -105,7 +105,7 @@ Find a matrix $A$ so that $A\ket{\texttt{ab}}$ works as expected. \par
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\vfill
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\pagebreak
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\generic{Remark:}
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\cgeneric{Remark}
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The way a quantum circuit handles information is a bit different than the way a classical circuit does.
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We usually think of logic gates as \textit{functions}: they consume one set of bits, and return another:
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@ -275,7 +275,7 @@ Find the matrix that corresponds to the above transformation. \par
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\vfill
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\generic{Remark:}
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\cgeneric{Remark}
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We could draw the above transformation as a combination $X$ and $I$ (identity) gate:
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\begin{center}
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\begin{tikzpicture}[scale=0.8]
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@ -127,7 +127,7 @@ If we measure the result of \ref{applycnot}, what are the probabilities of getti
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\vfill
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\generic{Remark:}
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\cgeneric{Remark}
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As we just saw, a quantum gate is fully defined by the place it maps our basis states $\ket{0}$ and $\ket{1}$ \par
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(or, $\ket{00...0}$ through $\ket{11...1}$ for multi-qubit gates). This directly follows from \ref{qgateislinear}.
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@ -576,6 +576,16 @@
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\IfNoValueF{#2}{\@customlabel{#2}{#1}}
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}
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% Problem-counter generic object.
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% Same format as \problem, \theorem, etc, but has a counter.
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\NewDocumentCommand{\cgeneric}{ m d<> }{
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\stepcounter{\@problemcounter}
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\par
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\vspace{3mm}
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{\bf\normalsize #1 \arabic{\@problemcounter}:} \\*
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\IfNoValueF{#2}{\@customlabel{#2}{#1}}
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}
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% Make a new section type.
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% Args: command, counter, title.
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\newcommand\@newobj[3]{
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