ORMCbox fix

Advanced/Introduction to Quantum/parts/02.00 half a qubit.tex

@@ -47,7 +47,7 @@ However, \texttt{0} and \texttt{1} aren't the only states a qubit may have.
 We'll make sense of quantum bits by extending the \say{vectored} bit representation we developed in the previous section.
 First, let's look at a diagram we drew a few pages ago:
 
-\begin{timetravel}
+\begin{ORMCbox}{Time Travel (Page 2)}{black!10!white}{black!65!white}
 	A classical bit takes states in $\{\texttt{0}, \texttt{1}\}$, picking one at a time. \par
 	We'll represent \texttt{0} and \texttt{1} as perpendicular unit vectors $\ket{0}$ and $\ket{1}$,
 	show below.
@@ -72,7 +72,7 @@ First, let's look at a diagram we drew a few pages ago:
 	The point marked $1$ is at $[0, 1]$. It is no parts $\ket{0}$, and all parts $\ket{1}$. \par
 	Of course, we can say something similar about the point marked $0$: \par
 	It is at $[1, 0] = (1 \times \ket{0}) + (0 \times \ket{1})$, and is thus all $\ket{0}$ and no $\ket{1}$. \par
-\end{timetravel}
+\end{ORMCbox}
 
 The diagram in the box above can also be used to describe the state of a qubit. \par
 Like classical bits, qubits have the \textit{basis states} $\ket{0}$ and $\ket{1}$. \par