Minor edits
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		| @ -2,7 +2,7 @@ | ||||
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| \definition{} | ||||
| Just as before, we'll represent multi-quibit states as linear combinations of multi-qubit basis states. \par | ||||
| Just as before, we'll represent multi-qubit states as linear combinations of multi-qubit basis states. \par | ||||
| For example, a two-qubit state $\ket{ab}$ is the four-dimensional unit vector | ||||
| \begin{equation} | ||||
| 	\begin{bmatrix} | ||||
| @ -33,7 +33,7 @@ we get one of the four basis states with the following probabilities: | ||||
| 	\item $\mathcal{P}(\ket{10}) = c^2$ | ||||
| 	\item $\mathcal{P}(\ket{11}) = d^2$ | ||||
| \end{itemize} | ||||
| Of course, the sum of all the above probabilities is $1$. | ||||
| As before, the sum of all the above probabilities is $1$. | ||||
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| \problem{} | ||||
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| @ -26,11 +26,11 @@ map, we can write it as follows: | ||||
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| \definition{} | ||||
| Before we discussing multi-qubit quantum gates, we need to review to classical logic. \par | ||||
| Of course, a classical logic gate is a linear map from $\mathbb{B}^m$ to $\mathbb{B}^n$ | ||||
| Of course, a classical logic gate is a linear map from $\{0,1\}^m$ to $\{0,1\}^n$ | ||||
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| \problem{}<notgatex> | ||||
| The \texttt{not} gate is a map from $\mathbb{B}$ to $\mathbb{B}$ defined by the following table: \par | ||||
| The \texttt{not} gate is a map defined by the following table: \par | ||||
|  | ||||
| \begin{itemize} | ||||
| 	\item $X\ket{0} = \ket{1}$ | ||||
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| @ -10,7 +10,7 @@ satisfies $GG^\text{T} = I$. \par | ||||
| This implies the following: \par | ||||
|  | ||||
| \begin{itemize} | ||||
| 	\item $G$ is square \par | ||||
| 	\item $G$ is square. In other words, it has as many rows as it has columns. \par | ||||
| 	\note{ | ||||
| 		If we think of $G$ as a map, this means that $G$ has as many inputs as it has outputs. \\ | ||||
| 		This is to be expected: we stated earlier that quantum gates do not destroy or create qubits. | ||||
| @ -29,7 +29,7 @@ We can restate the above definition as follows: \par | ||||
| A quantum gate is an invertible map from $\mathbb{U}^n$ to $\mathbb{U}^n$. | ||||
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| \definition{}<qgateislinear> | ||||
| \generic{Remark:} | ||||
| Let $G$ be a quantum gate. \par | ||||
| Since quantum gates are, by definition, \textit{linear} maps, | ||||
| the following holds: \par | ||||
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| @ -53,6 +53,7 @@ The $Z$ gate is defined as follows: \par | ||||
| \problem{} | ||||
| Suppose that Alice and Bob are each in possession of one qubit. \par | ||||
| These two qubits are entangled, and have the compound state $\ket{\Phi^+}$. \par | ||||
| \note[Note]{We could say that they each have \say{half} of $\ket{\Phi^+}$.} | ||||
| How can Alice send a two-bit classical state | ||||
| (i.e, one of the four values \texttt{00}, \texttt{01}, \texttt{10}, \texttt{11}) \par | ||||
| to Bob by only sending one qubit? | ||||
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