diff --git a/Advanced/Tropical Polynomials/macros.typ b/Advanced/Tropical Polynomials/macros.typ
index 7156bf9..db144b1 100644
--- a/Advanced/Tropical Polynomials/macros.typ	
+++ b/Advanced/Tropical Polynomials/macros.typ	
@@ -1,4 +1,5 @@
 #import "@preview/cetz:0.3.1"
+#import "handout.typ": *
 
 // Shorthand, we'll be using these a lot.
 #let tp = sym.plus.circle
@@ -35,3 +36,34 @@
     ),
   )
 }
+
+/// Adds extra padding to an equation.
+/// Used as follows:
+///
+/// #eqmbox($
+///   f(x) = -2(x #tp 2)(x #tp 8)
+/// $)
+///
+/// Note that there are newlines between the $ and content,
+/// this gives us display math (which is what we want when using this macro)
+#let eqnbox(eqn) = {
+  align(
+    center,
+    box(
+      inset: 3mm,
+      eqn,
+    ),
+  )
+}
+
+#let dotline(a, b) = {
+  cetz.draw.line(
+    a,
+    b,
+    stroke: (
+      dash: "dashed",
+      thickness: 0.5mm,
+      paint: ored,
+    ),
+  )
+}
diff --git a/Advanced/Tropical Polynomials/parts/01 polynomials.typ b/Advanced/Tropical Polynomials/parts/01 polynomials.typ
index 82f6cf3..6000de5 100644
--- a/Advanced/Tropical Polynomials/parts/01 polynomials.typ	
+++ b/Advanced/Tropical Polynomials/parts/01 polynomials.typ	
@@ -72,36 +72,9 @@ Draw a graph of the tropical polynomial $f(x) = x^2 #tp 1x #tp 4$. \
     import cetz.draw: *
     let step = 0.75
 
-    line(
-      (0, 0),
-      (4 * step, 8 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
-
-    line(
-      (0, 1 * step),
-      (7 * step, 8 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
-
-    line(
-      (0, 4 * step),
-      (8 * step, 4 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
-
+    dotline((0, 0), (4 * step, 8 * step))
+    dotline((0, 1 * step), (7 * step, 8 * step))
+    dotline((0, 4 * step), (8 * step, 4 * step))
 
     line((0, 0), (1 * step, 2 * step), (3 * step, 4 * step), (7.5 * step, 4 * step), stroke: 1mm + oblue)
   })
@@ -161,35 +134,9 @@ Graph $f(x) = -2x^2 #tp x #tp 8$. \
     import cetz.draw: *
     let step = 0.75
 
-    line(
-      (0, 0),
-      (8 * step, 8 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
-
-    line(
-      (0.5 * step, 0),
-      (4 * step, 8 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
-
-    line(
-      (0, 4 * step),
-      (8 * step, 4 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
+    dotline((0, 0), (8 * step, 8 * step))
+    dotline((0.5 * step, 0), (4 * step, 8 * step))
+    dotline((0, 4 * step), (8 * step, 4 * step))
 
     line((0.5 * step, 0), (1 * step, 1 * step), (4 * step, 4 * step), (7.5 * step, 4 * step), stroke: 1mm + oblue)
   })
@@ -201,23 +148,15 @@ Find a factorization of $f$ in the form $a(x #tp r)(x#tp s)$.
 #solution([
   We (tropically) factor out $-2$ to get
 
-  #align(
-    center,
-    box(
-      inset: 3mm,
-      $f(x) = -2(x^2 #tp 2x #tp 10)$,
-    ),
-  )
+  #eqnbox($
+    f(x) = -2(x^2 #tp 2x #tp 10)
+  $)
+
 
   by the same process as the previous problem, we get
-
-  #align(
-    center,
-    box(
-      inset: 3mm,
-      $f(x) = -2(x #tp 2)(x #tp 8)$,
-    ),
-  )
+  #eqnbox($
+    f(x) = -2(x #tp 2)(x #tp 8)
+  $)
 ])
 
 #v(1fr)
@@ -269,35 +208,9 @@ Graph $f(x) = 1x^2 #tp 3x #tp 5$.
     import cetz.draw: *
     let step = 0.75
 
-    line(
-      (0, 1 * step),
-      (3.5 * step, 8 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
-
-    line(
-      (0, 4 * step),
-      (8 * step, 4 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
-
-    line(
-      (0, 3 * step),
-      (5 * step, 8 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
+    dotline((0, 1 * step), (3.5 * step, 8 * step))
+    dotline((0, 5 * step), (8 * step, 5 * step))
+    dotline((0, 3 * step), (5 * step, 8 * step))
 
     line((0, 1 * step), (2 * step, 5 * step), (7.5 * step, 5 * step), stroke: 1mm + oblue)
   })
@@ -308,13 +221,9 @@ Graph $f(x) = 1x^2 #tp 3x #tp 5$.
 Find a factorization of $f$ in the form $a(x #tp r)(x#tp s)$.
 
 #solution(
-  align(
-    center,
-    box(
-      inset: 3mm,
-      $f(x) = 1x^2 #tp 3 x #tp 5 = 1(x #tp 2)^2$,
-    ),
-  ),
+  eqnbox($
+    f(x) = 1x^2 #tp 3 x #tp 5 = 1(x #tp 2)^2
+  $),
 )
 
 #v(1fr)
@@ -343,35 +252,9 @@ Graph $f(x) = 2x^2 #tp 4x #tp 4$.
     import cetz.draw: *
     let step = 0.75
 
-    line(
-      (0, 2 * step),
-      (3 * step, 8 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
-
-    line(
-      (0, 4 * step),
-      (5 * step, 8 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
-
-    line(
-      (0, 4 * step),
-      (8 * step, 4 * step),
-      stroke: (
-        dash: "dashed",
-        thickness: 0.5mm,
-        paint: ored,
-      ),
-    )
+    dotline((0, 2 * step), (3 * step, 8 * step))
+    dotline((0, 4 * step), (5 * step, 8 * step))
+    dotline((0, 4 * step), (8 * step, 4 * step))
 
     line((0, 2 * step), (1 * step, 4 * step), (7.5 * step, 4 * step), stroke: 1mm + oblue)
   }),