Mockingbird edits
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@ -8,7 +8,7 @@ Bird $AB$ is, by definition, $A$'s response to $B$.
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As you wander around this forest, you quickly discover two interesting facts:
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\begin{enumerate}[itemsep = 1mm]
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\item $A$'s responds to $B$ mustn't be the same as $B$'s response to $A$.
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\item $A$'s response to $B$ mustn't be the same as $B$'s response to $A$.
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\item Given three birds $A$, $B$, and $C$, $(AB)C$ and $A(BC)$ are not necessarily the same bird. \\
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Bird $A(BC)$ is $A$'s response to bird $BC$, while $(AB)C$ is $AB$'s response to $C$. \\
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Thus, $ABC$ is ambiguous. Parenthesis are mandatory.
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@ -29,7 +29,7 @@ Complete his proof.
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\vfill
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\problem{}
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We say a bird $A$ is \textit{egocentric} if it is fond if itself. \\
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We say a bird $A$ is \textit{egocentric} if it is fond of itself. \\
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Show that the laws of the forest guarantee that at least one bird is egocentric.
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@ -56,7 +56,7 @@ Show that the laws of the forest guarantee that at least one bird is egocentric.
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\definition{}
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We say a bird $A$ is \textit{agreeable} if for all birds $B$, there is at least one bird $x$ on which $A$ and $B$ agree. \\
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In other words, $A$ is agreeable if $Ax = Bx$ for some $x$ for all $B$.
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In other words, $A$ is agreeable if given any $B$, we can find a bird $x$ satisfying $Ax = Bx$.
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\problem{}
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Is the Mockingbird agreeable?
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@ -71,7 +71,7 @@ Is the Mockingbird agreeable?
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\problem{}
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Take two birds $A$ and $B$. Let $C$ be their composition. \\
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Show that $A$ must be agreeable if $C$ is agreeable.
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Show that if $C$ is agreeable, $A$ is agreeable.
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\begin{alltt}
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\cmnt{Given information}
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let A, B
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@ -125,9 +125,11 @@ Given three arbitrary birds $A$, $B$, and $C$, show that there exists a bird $D$
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\vfill
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\problem{}
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\definition{}
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We say two birds $A$ and $B$ are \textit{compatible} if there are birds $x$ and $y$ so that $Ax = y$ and $By = x$. \\
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Note that $x$ and $y$ may be the same bird. \\
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\problem{}
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Show that any two birds in this forest are compatible. \\
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\begin{alltt}
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let A, B
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@ -28,12 +28,12 @@ Say $A$ is fixated on $B$. Is $A$ fond of $B$?
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\definition{}
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The \textit{Kestrel} $K$ is defined by the following relationship:
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$$
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(Kx)y = x
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(Kx)y = x~~~\forall x, y
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$$
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In other words, this means that for every bird $x$, the bird $Kx$ is fixated on $x$.
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\problem{}
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Show that an egocenteric Kestrel is hopelessly egocentric
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Show that an egocenteric Kestrel is hopelessly egocentric.
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\begin{solution}
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\begin{alltt}
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