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@ -205,12 +205,6 @@ Is this function one-to-one? Is it onto?
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\vfill
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\problem{}
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Consider the function $f: \mathbb{N} \to \mathbb{N}$ defined by $f(x) = x^2$. \par
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Is this function one-to-one? Is it onto?
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\vfill
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\problem{}
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Consider the function $f: \mathbb{Z} \to \mathbb{Z}$ defined below. \par
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Is this function one-to-one? Is it onto?
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@ -375,4 +369,7 @@ Show that no bijection between $A$ and $B$ exists.
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Intuitively, you can think of a bijection as a \say{matching} between elements of $A$ and $B$. If we were to draw a bijection, we'd see an arrow connecting every element in $A$ to every element in $B$. If a bijection exists, every element of $A$ directly corresponds to an element of $B$, therefore $A$ and $B$ must have the same number of elements.
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\definition{}
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We say two sets $A$ and $B$ are \textit{equinumerous} if there exists a bijection $f: A \to B$.
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\pagebreak
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