Minor cleanup

Advanced/Random Walks/parts/3 effective.tex

@@ -250,9 +250,10 @@ If we place $A$ and $B$ at opposing vertices, what is the effective resistance o
 	There are $\binom{n}{k}$ nodes in the $k^\text{th}$ layer. Each node in this layer has $k$ ones, so
 	there are $n - k$ ways to flip a zero to get to the $(k + 1)^\text{th}$ layer. In total, there are 
 	$\binom{n}{k}(n - k)$ parellel connections from the $k^\text{th}$ layer to the $(k + 1)^\text{th}$
-	layer, creating an effective resistance of $(\binom{n}{k}(n - k))^{-1}$.
-
-	\vspace{2mm}
+	layer, creating an effective resistance of 
+	$$
+		\frac{1}{\binom{n}{k}(n - k)}
+	$$
 
 	The total effective resistance is therefore
 	$$
@@ -263,7 +264,7 @@ If we place $A$ and $B$ at opposing vertices, what is the effective resistance o
 
 	To calculate the limit as $n \rightarrow \infty$, note that
 	$$
-		\binom{n}{k}(n - k) = \frac{n!}{(n - k - 1)! \times k!} = n \binom{n-1}{k}.
+		\binom{n}{k}(n - k) = \frac{n!}{(n - k - 1)! \times k!} = n \binom{n-1}{k}
 	$$
 	So, the sum is
 	$$